Message #1458

From: Roice Nelson <roice3@gmail.com>
Subject: Re: [MC4D] Social dream
Date: Sat, 26 Feb 2011 15:15:19 -0600

Hi Andy,

I think the calculation for count of symmetry axes for the tesseract goes
like this:

count = ( 8 + 24 + 32 + 16 ) / 2 = 40

8 cells
24 faces
32 edges
16 vertices

You divide by two because each axis gets counted twice in the sum, due to
antipodal elements.

Cheers,
Roice

On Fri, Feb 25, 2011 at 5:09 PM, Andrew Gould <agould@uwm.edu> wrote:

>
>
> I’m seeing 46 rotational planes for the tesseract (6 planes for 90-degree
> rotations, 24 for 180-degree, 16 for 120-degree), now I’m trying to
> translate into Andrey’s 40 axes–I got confused.
>
>
>
> I’m keeping my so-called "2D twists" in mind. They seem to use the same
> axes/rotational planes that are already used.
>
> http://groups.yahoo.com/group/4D_Cubing/photos/album/1774759718/pic/list
>
>
>
> The deal in 5D is that you can twist 4D slices, 3D slices, or 2D
> slices…but again I’m seeing that they all get twisted about
> axes/rotational planes that are already used for twisting 4D slices.
>
>
>
> –
>
> Andy
>