Message #2099

From: "charliemckiz@rocketmail.com" <charliemckiz@rocketmail.com>
Subject: Calculating the number of permutation of 2by2by2by2by2 (2^5)
Date: Wed, 02 May 2012 17:46:06 -0000

2x2x2x2x2

(31!/2)(60^31) =

54535655175308197058635263389110963213764726777446400000000000000000000000000000000000000

approx. = 5.4 x 10^88

Should the 31 be 32?

Mine is

32!/2*(5!/2)^(32) =

104708457936591738352579705707093049370428275412697088000000000000000000000000000000000000000

approx. = 1.0 x 10^92