Message #706

From: "thesamer@interia.pl" <thesamer@interia.pl>
Subject: Re: [MC4D] Re: 3^4 parity problems
Date: Sun, 18 Oct 2009 11:19:17 +0200

Hello,

To solve problems with various scrambles, simply do what I was doing:
just take scramble which was used to previous record! This way it will
be legitimate "shortest solve" because based on the same ground state.
(I don’t think that on 3^4 you can get something better from choosing
starting state, the cube is to complex. I was almost magical when I was
beating previous Rocie record with 334 twists and we were finishing
stages 2C, 3C and 4C varying only by 1 twist! and my final result was
333 twists). On 2^4 there is a little different story and I encourage
you to take record scramble and work on it.

On 3^4 I don’t think that method which starts with 4C will give good
result. Believe me - I was there :). Algorithms which not move 4C’s and
concerns only other pieces are to much twist consuming.

Method which I’ve used in order to break previous Roice solution (334
twists) was basicly "Roice solution" but with only using two algorithms
and a lot of thinking on preliminary moves to solve 3 or more pieces 3C
(very nasty alg which shuffles eight 3C but has only 4 twists) and 2
pieces of 4C at the same time in one algorithm. I must say it -> 300
twists is a boundary of such kind of approach. It just like Fridrich on
3^3 and 30 twists there. There are steps which you have to go through
(2C, 3C and 4C), not breaking what you build already and there is no way
to comprehend and deal with pieces (my preliminary moves was taking more
twists than algorithm.

My next try on Roice record in 3^4 will be Layer by Layer (ok, partly
layer) method :) and be sure I want my shortest 2^4 back as well :P

Congratulations on all new records and good luck with new tries!

All the best,
Remi

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